It is just two ! boolean not operators sitting next to each other. The reason to use this idiom is to make sure that you receive a 1 or a 0. Actually it returns an empty string which numifys to 0. It’s usually only used in numeric, or boolean context though. You will often see … Read more
short answer: YES Ref: http://docs.scipy.org/doc/numpy/reference/generated/numpy.invert.html Notice: Computes the bit-wise NOT of the underlying binary representation of the integers in the input arrays. This ufunc implements the C/Python operator ~. and bitwise_not is an alias for invert: >> np.bitwise_not is np.invert >> True
Both of the span elements’ parent div elements don’t have the class no, regardless of whether any other ancestors do have it or not: <div> <!– This is div:not(.no), pretty much a given –> <span>yes 1</span> </div> <div class=”no”> <!– In this case, although this is div.no… –> <div> <!– … this is div:not(.no)! –> … Read more
The negation operator in Python is not. Therefore just replace your ! with not. For your example, do this: if not os.path.exists(“/usr/share/sounds/blues”) : proc = subprocess.Popen([“mkdir”, “/usr/share/sounds/blues”]) proc.wait() For your specific example (as Neil said in the comments), you don’t have to use the subprocess module, you can simply use os.mkdir() to get the result … Read more
Very close! In your select expression, you have to use a pipe (|) before contains. This filter produces the expected output. . – map(select(.Names[] | contains (“data”))) | .[] .Id The jq Cookbook has an example of the syntax. Filter objects based on the contents of a key E.g., I only want objects whose genre … Read more