The chosen answer is no longer valid when you try overloads using the == operator in the new version. Now you need to do this: class MyClass { @override bool operator ==(other) { // compare this to other } } But it’s not safe. other is not specified as a type, Something unexpected may happened. … Read more
Overloading generally means that you have two or more functions in the same scope having the same name. The function that better matches the arguments when a call is made wins and is called. Important to note, as opposed to calling a virtual function, is that the function that’s called is selected at compile time. … Read more
Overloading constructors isn’t special for case classes: case class Foo(bar: Int, baz: Int) { def this(bar: Int) = this(bar, 0) } new Foo(1, 2) new Foo(1) However, you may like to also overload the apply method in the companion object, which is called when you omit new. object Foo { def apply(bar: Int) = new … Read more
For Python 2.x reload(foo) For Python 3.x import importlib import foo #import the module here, so that it can be reloaded. importlib.reload(foo)
Definitely a matter of style. I prefer constructors with default parameters, so long as the parameters make sense. Classes in the standard use them as well, which speaks in their favor. One thing to watch out for is if you have defaults for all but one parameter, your class can be implicitly converted from that … Read more
You can either Widen or Box but you cannot do both, unless you are boxing and widening to Object (An int to Integer(Boxing) and then Integer to Object(Widening) is legal, since every class is a subclass of Object, so it is possible for Integer to be passed to Object parameter) Similarly an int to Number … Read more
When you do new Foo() then two things happen: First operator new is invoked to allocate memory, then a constructor for Foo is called. If that constructor throws, since you cannot access the memory already allocated, the C++ runtime will take care of it by passing it to the appropriate operator delete. That’s why you … Read more
TTBOMK this doesn’t have a real technical reason, it’s just that Stroustrup, when creating the language, considered this to be the better default. (In this it’s similar to the rule that rvalues do not implicitly bind to non-const references.) You can easily work around it be explicitly bringing base class versions into the derived class’ … Read more
Unfortunately, no As i’m sure you’re aware, but I’ll state explicitly for completeness – there are only the 2 keywords to control the method invocation: this – this.method() – looks for method starting from the invoking instance’s class (the instance’s “top” virtual table – implied default) super – super.method() – looks for method starting from … Read more
You could write a convenience method: public PrintStream print(String format, Object… arguments) { return System.out.format(format, arguments); } But as you can see, you’ve simply just renamed format (or printf). Here’s how you could use it: private void printScores(Player… players) { for (int i = 0; i < players.length; ++i) { Player player = players[i]; String … Read more