I can solve that problem – with trigonometry :). See fiddle: http://jsfiddle.net/nrabinowitz/GQDUS/ Basically, calling arc.centroid(d) returns an [x,y] array. You can use the Pythagorean Theorem to calculate the hypotenuse, which is the length of the line from the center of the pie to the arc centroid. Then you can use the calculations x/h * desiredLabelRadius … Read more
I would approach this by defining another variable (which I call pos) in df that calculates the position of text labels. I do this with dplyr but you could also use other methods of course. library(dplyr) library(ggplot2) df <- df %>% group_by(year) %>% mutate(pos = cumsum(quantity)- quantity/2) ggplot(data=df, aes(x=factor(1), y=quantity, fill=factor(prod))) + geom_bar(stat=”identity”) + geom_text(aes(x= … Read more
Edit 2 My original answer is really dumb. Here is a much shorter version which does most of the work with a much simpler interface. #’ x numeric vector for each slice #’ group vector identifying the group for each slice #’ labels vector of labels for individual slices #’ col colors for each group … Read more
New answer 2021 With some modern techniques we can improve the code. You can have rounded edges and also consider animation: @property –p{ syntax: ‘<number>’; inherits: true; initial-value: 1; } .pie { –p:20; /* the percentage */ –b:22px; /* the thickness */ –c:darkred; /* the color */ –w:150px; /* the size*/ width:var(–w); aspect-ratio:1/1; position:relative; display:inline-grid; … Read more
NEW ANSWER: With the introduction of ggplot2 v2.2.0, position_stack() can be used to position the labels without the need to calculate a position variable first. The following code will give you the same result as the old answer: ggplot(data = dat, aes(x = “”, y = Cnt, fill = Volume)) + geom_bar(stat = “identity”) + … Read more
First I would recreate this with less of code relying on clip-path like below: .palette { height: 200px; width: 200px; position:relative; overflow:hidden; } .palette > * { position:absolute; top:0; left:0; right:0; bottom:0; border:50px solid var(–c,red); border-radius:50%; clip-path:polygon(50% 50%, 50% 0%, 100% 0%,100% 33.745%); } .color1 { transform:rotate(72deg); –c:blue; } .color2 { transform:rotate(144deg); –c:orange; } .color3 … Read more
Because I really don’t understand Turbo C++ I can’t say for sure. But I think this is your solution: void Circular_arc(constint h, constint k, constint r, constint start_angle, constint end_angle) { static int offset = 0; start_angle = (start_angle + offset) % 360; end_angle = (end_angle + offset) % 360; offset = end_angle; int color … Read more