When you say fetch(‘data.json’) you are effectively requesting http://yourdomain.com/data.json since it is relative to the page you’re are making the request from. You should lead with forward slash, which will indicate that the path is relative to the domain root: fetch(‘/js/data.json’). Or fully qualify with your domain fetch(‘http://yourdomain.com/js/data.json’).
I don’t believe you can load the DLL directly from the JAR. You have to take the intermediary step of copying the DLL out of the JAR. The following code should do it: public static void loadJarDll(String name) throws IOException { InputStream in = MyClass.class.getResourceAsStream(name); byte[] buffer = new byte[1024]; int read = -1; File … Read more
The solution is to use __file__ and it’s pretty clean: import os TEST_FILENAME = os.path.join(os.path.dirname(__file__), ‘test.txt’)
Make sure that your resource folder is listed as a source folder in your project settings. Also, make sure that the resource folder is set to export when you build your jar. You can add a .zip extension to your jar file then open it up to ensure that your resources are included and at … Read more
Take a look at the following info from PEP 328: Relative imports use a module’s __name__ attribute to determine that module’s position in the package hierarchy. If the module’s name does not contain any package information (e.g. it is set to ‘__main__’) then relative imports are resolved as if the module were a top level … Read more
After fiddling with it a bit more, I realized how to set it up, and for the sake of specificity I won’t use foo bar names. My project directory is set up as… tools/ core/ object_editor/ # files that need to use ntlib.py editor.py # see example at bottom __init__.py state_editor/ # files that need … Read more
you should use a config file that will be included in each file first line, for example your app look like this root / App / Plugins inside your root dir : app-config.php if ( !defined(‘ABSPATH’) ) define(‘ABSPATH’, dirname(__FILE__) . “https://stackoverflow.com/”); now, suppose you have to include a plugin file, so inside your Plugin dir … Read more
CssRewriteUrlTransform updates the CSS Url with absolute path, saying so if we use – bundles.Add(new StyleBundle(“~/Content/css”).Include(“~/Content/site.css”,new CssRewriteUrlTransform())); and we have following CSS class in “site.css” .Sandy { background-image: url(“Images/Sandy.jpg”); border: 1px solid #c8c8c8; border-radius:4px 4px 4px 4px; box-shadow: 1px 1px 8px gray; background-position:left; background-size:contain; -moz-background-size:contain; -webkit-background-size:contain; -o-background-size:contain; background-repeat:no-repeat; min-height:100px; min-width:100px; display:block; } and following folder … Read more
Try this one: function getRelativePath($from, $to) { // some compatibility fixes for Windows paths $from = is_dir($from) ? rtrim($from, ‘\/’) . “https://stackoverflow.com/” : $from; $to = is_dir($to) ? rtrim($to, ‘\/’) . “https://stackoverflow.com/” : $to; $from = str_replace(‘\\’, “https://stackoverflow.com/”, $from); $to = str_replace(‘\\’, “https://stackoverflow.com/”, $to); $from = explode(“https://stackoverflow.com/”, $from); $to = explode(“https://stackoverflow.com/”, $to); $relPath = $to; … Read more
You need “src/Hankees.txt” Your file is in the source folder which is not counted as the working directory.\ Or you can move the file up to the root directory of your project and just use “Hankees.txt”