.NET 4+ IList<string> strings = new List<string>{“1″,”2″,”testing”}; string joined = string.Join(“,”, strings); Detail & Pre .Net 4.0 Solutions IEnumerable<string> can be converted into a string array very easily with LINQ (.NET 3.5): IEnumerable<string> strings = …; string[] array = strings.ToArray(); It’s easy enough to write the equivalent helper method if you need to: public static … Read more
Like this: if (str.indexOf(“Yes”) >= 0) …or you can use the tilde operator: if (~str.indexOf(“Yes”)) This works because indexOf() returns -1 if the string wasn’t found at all. Note that this is case-sensitive. If you want a case-insensitive search, you can write if (str.toLowerCase().indexOf(“yes”) >= 0) Or: if (/yes/i.test(str)) The latter is a regular expression … Read more
str(0.47000000000000003) give ‘0.47’ and float(‘0.47’) can be 0.46999999999999997. This is due to the way floating point number are represented (see this wikipedia article) Note: float(repr(0.47000000000000003)) or eval(repr(0.47000000000000003)) will give you the expected result, but you should use Decimal if you need precision.
Yes, strtok(), indeed, uses some static memory to save its context between invocations. Use a reentrant version of strtok(), strtok_r() instead, or strtok_s() if you are using VS (identical to strtok_r()). It has an additional context argument, and you can use different contexts in different loops. char *tok, *saved; for (tok = strtok_r(str, “%”, &saved); … Read more
The following works invoke it as select * from table(splitter(‘a,b,c,d’)) create or replace function splitter(p_str in varchar2) return sys.odcivarchar2list is v_tab sys.odcivarchar2list:=new sys.odcivarchar2list(); begin with cte as (select level ind from dual connect by level <=regexp_count(p_str,’,’) +1 ) select regexp_substr(p_str,'[^,]+’,1,ind) bulk collect into v_tab from cte; return v_tab; end; /
The reason this happens is because of the order in which the shell parses the command line: it parses (and removes) quotes and escapes, then replaces variable values. By the time $test gets replaced with One “This is two” Three, it’s too late for the quotes to have their intended effect. The simple (but dangerous) … Read more
It’s called “string pooling”. It’s optional in Microsoft Compilers, but not in GCC. If you switch off string pooling in MSVC, then the “same” strings in the different arrays would be duplicated, and have different memory addresses, and so would take up an extra (unnecessary) 50 or so bytes of your static data. EDIT: gcc … Read more
Here is one way substring(“aabbccccdd”, seq(1, 9, 2), seq(2, 10, 2)) #[1] “aa” “bb” “cc” “cc” “dd” or more generally text <- “aabbccccdd” substring(text, seq(1, nchar(text)-1, 2), seq(2, nchar(text), 2)) #[1] “aa” “bb” “cc” “cc” “dd” Edit: This is much, much faster sst <- strsplit(text, “”)[[1]] out <- paste0(sst[c(TRUE, FALSE)], sst[c(FALSE, TRUE)]) It first splits … Read more
Try this if(gender.equals(“Male”)) salutation =”Mr.”; if(gender.equals(“Female”)) salutation =”Ms.”; Also remove ;(semi-colon ) in your if statement if(gender.equals(g1)); In Java, one of the most common mistakes newcomers meet is using == to compare Strings. You have to remember, == compares the object references, not the content.
No need to use str.replace or string.replace here, just convert that string to a raw string: >>> strs = r”C:\Users\Josh\Desktop\20130216″ ^ | notice the ‘r’ Below is the repr version of the above string, that’s why you’re seeing \\ here. But, in fact the actual string contains just ‘\’ not \\. >>> strs ‘C:\\Users\\Josh\\Desktop\\20130216’ >>> … Read more