You can use Integer.parseInt with a radix of 2 (binary) to convert the binary string to an integer: int charCode = Integer.parseInt(info, 2); Then if you want the corresponding character as a string: String str = new Character((char)charCode).toString();
This function does the job of only returning the digits 0-9 from the string, which does the job nicely to solve your issue, regardless of what prefixes or postfixes you have. http://www.artfulsoftware.com/infotree/queries.php?&bw=1280#815 Copied here for reference: SET GLOBAL log_bin_trust_function_creators=1; DROP FUNCTION IF EXISTS digits; DELIMITER | CREATE FUNCTION digits( str CHAR(32) ) RETURNS CHAR(32) BEGIN … Read more
$_DB[‘password’] = ‘mypas$word’; Single quote strings are not processed and are taken “as-is”. You should always use single quote strings unless you specifically need the $variable or escape sequences (\n, \r, etc) substitutions. It’s faster and less error prone.
You have no storage allocated for word – it’s just a dangling pointer. Change: char * word; to: char word[256]; Note that 256 is an arbitrary choice here – the size of this buffer needs to be greater than the largest possible string that you might encounter. Note also that fgets is a better (safer) … Read more
It doesn’t – the C# compiler does 🙂 So this code: string x = “hello”; string y = “there”; string z = “chaps”; string all = x + y + z; actually gets compiled as: string x = “hello”; string y = “there”; string z = “chaps”; string all = string.Concat(x, y, z); (Gah – … Read more
In XSLT 1.0 the upper-case() and lower-case() functions are not available. If you’re using a 1.0 stylesheet the common method of case conversion is translate(): <xsl:variable name=”lowercase” select=”‘abcdefghijklmnopqrstuvwxyz'” /> <xsl:variable name=”uppercase” select=”‘ABCDEFGHIJKLMNOPQRSTUVWXYZ'” /> <xsl:template match=”https://stackoverflow.com/”> <xsl:value-of select=”translate(doc, $lowercase, $uppercase)” /> </xsl:template>
A simple loop works well: var str = “scissors”; var indices = []; for(var i=0; i<str.length;i++) { if (str[i] === “s”) indices.push(i); } Now, you indicate that you want 1,4,5,8. This will give you 0, 3, 4, 7 since indexes are zero-based. So you could add one: if (str[i] === “s”) indices.push(i+1); and now it … Read more
I would approach this by using re.match in the following way: import re match = re.match(r”([a-z]+)([0-9]+)”, ‘foofo21’, re.I) if match: items = match.groups() print(items) >> (“foofo”, “21”)
You need to use DateTime.ParseExact with format “dd/MM/yyyy” DateTime dt=DateTime.ParseExact(“24/01/2013”, “dd/MM/yyyy”, CultureInfo.InvariantCulture); Its safer if you use d/M/yyyy for the format, since that will handle both single digit and double digits day/month. But that really depends if you are expecting single/double digit values. Your date format day/Month/Year might be an acceptable date format for some … Read more
In Objective-C, the syntax @”foo” is an immutable, literal instance of NSString. It does not make a constant string from a string literal as Mike assume. Objective-C compilers typically do intern literal strings within compilation units — that is, they coalesce multiple uses of the same literal string — and it’s possible for the linker … Read more