Came across this question while searching for my own answer. I thought I’d leave my solution here since it’s another way to accomplish the same task and may be more efficient. The trick is the self join using >= SELECT s1.ID, s1.name, s1.money, sum(s2.money) as accumulator FROM student s1 INNER JOIN student s2 ON s1.id … Read more
Typically you generate 4 partial sums in your loop and then just sum horizontally across the 4 elements after the loop, e.g. #include <cassert> #include <cstdint> #include <emmintrin.h> float vsum(const float *a, int n) { float sum; __m128 vsum = _mm_set1_ps(0.0f); assert((n & 3) == 0); assert(((uintptr_t)a & 15) == 0); for (int i = … Read more
Yes you can. Go over all pairs of numbers and store their sum(and also store which numbers give that sum). After that for each sum check if its negation is found among the sums you have. Using a hash you can reach quadratic complexity, using std::map, you will reach O(n^2*log(n)). EDIT: to make sure no … Read more
if the time in hh/mm/ss then :: SELECT studentid,studentname, DATEADD(ms, SUM(DATEDIFF(ms, ’00:00:00.000′, mytime)), ’00:00:00.000′) as time FROM worknote
SELECT color, fruit, sum(rating) FROM medleys GROUP BY color, fruit Distinct is used to select distinct elements, nothing more, while you want to aggregate and for that you need GROUP BY and aggregation functions (SUM).
You could use the Array.reduce method: const myData = [ [‘2013-01-22’, 0], [‘2013-01-29’, 0], [‘2013-02-05’, 0], [‘2013-02-12’, 0], [‘2013-02-19’, 0], [‘2013-02-26’, 0], [‘2013-03-05’, 0], [‘2013-03-12’, 0], [‘2013-03-19’, 0], [‘2013-03-26’, 0], [‘2013-04-02’, 21], [‘2013-04-09’, 2] ]; const sum = myData .map( v => v[1] ) .reduce( (sum, current) => sum + current, 0 ); console.log(sum); See … Read more
Updated for Pandas 0.24+ df.to_numpy().sum() Prior to Pandas 0.24+ df.values Is the underlying numpy array df.values.sum() Is the numpy sum method and is faster
Wrap them up and use subqueries: SELECT (SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900)+ (SELECT COUNT(*) from Games WHERE little_kid1 = 900 OR little_kid2 = 900 OR little_kid3 = 900) AS SumCount Voila!
Lets start with extracting a single cell at (row,col). If it is a single values, you can use the stats command to extract the values. The row and col are specified with every and using, like in a plot command. In your case, to extract the total value, use: # extract the ‘total’ cell stats … Read more