My suggestion is to always use DOMDocument as opposed to SimpleXML, since it’s a much nicer interface to work with and makes tasks a lot more intuitive. The following example shows you how to load the HTML into the DOMDocument object and query the DOM using XPath. All you really need to do is find … Read more
You can define a variable resolver and have the evaluation of the expression resolve variables such as $myvar, for example: XPathExpression expr = xpath.compile(“//doc[contains(., $myVar)]/*/text()”); There’s a fairly good explanation here. I haven’t actually done this before myself, so I might have a go and provide a more complete example. Update: Given this a go, … Read more
Or even better (and more portable), without the unnecessary prefix: /*/*[local-name()=’Books’] … and so on The function local-name ignores any prefix, which, as correctly stated by commenters, can vary.
Try this: //lemonade[@id=”1″]/price or //lemonade[@supplier=”mother”]/price Without the “@” it looks for child elements with that name instead of attributes.
I can’t find anything in the TXMLDocument documentation about XPath. XML example, from the OmniXML XPath demo: <?xml version=”1.0″ encoding=”UTF-8″?> <bookstore> <book> <title lang=”eng”>Harry Potter</title> </book> <book> <title lang=”eng”>Learning XML</title> </book> <book> <title lang=”slo”>Z OmniXML v lepso prihodnost</title> <year>2006</year> </book> <book> <title>Kwe sona standwa sam</title> </book> </bookstore> Try something like this: uses XMLDoc, XMLDom, XMLIntf; … Read more
AFAIK ElementTree does not support XPath. Has it changed? Anyway, you can use lxml and the following XPath expression: import lxml.etree doc = lxml.etree.parse(‘t.xml’) print doc.xpath(‘//element[text()=”A”]’)[0].text print doc.xpath(‘//element[text()=”A”]’)[0].tag The result will be: A element
The problem is the namespaces. When parsed as XML, the img tag is in the http://www.w3.org/1999/xhtml namespace since that is the default namespace for the element. You are asking for the img tag in no namespace. Try this: >>> tree.getroot().xpath( … “//xhtml:img”, … namespaces={‘xhtml’:’http://www.w3.org/1999/xhtml’} … ) [<Element {http://www.w3.org/1999/xhtml}img at 11a29e0>]
Use setNodeValue. First, get a NodeList, for example: myNodeList = (NodeList) xpath.compile(“//MyXPath/text()”) .evaluate(myXmlDoc, XPathConstants.NODESET); Then set the value of e.g. the first node: myNodeList.item(0).setNodeValue(“Hi mom!”); More examples e.g. here. As mentioned in two other answers here, as well as in your previous question: technically, XPath is not a way to “update” an XML document, but … Read more
This is a pretty common pattern: <xsl:for-each select=”*”> <xsl:value-of select=”.”/> <xsl:if test=”position() != last()”> <xsl:text>,</xsl:text> </xsl:if> </xsl:for-each>
HTML <div id=’a’> <div> <a class=”click”>abc</a> </div> </div> You could use the XPATH as : //div[@id=’a’]//a[@class=”click”] output <a class=”click”>abc</a> That said your Python code should be as : driver.find_element_by_xpath(“//div[@id=’a’]//a[@class=”click”]”)