Though the comments above are true regarding 1, 01, and 001, are all the same as an int, it can be very helpful in temporal modeling, or sequential movie making to maintain the leading zeros. I do it often to ensure movie clips are in proper order. The easy way to do that is using … Read more
-0 is (generally) treated as 0 *******. It can result when a negative floating-point number is so close to zero that it can be considered 0 (to be clear, I’m referring to arithmetic underflow, and the results of the following computations are interpreted as being exactly ±0, not just really small numbers). e.g. System.out.println(-1 / … Read more
I like if ((item.Rate ?? 0) == 0) { } Update 1: You could also define an extension method like: public static bool IsNullOrValue(this double? value, double valueToCheck) { return (value??valueToCheck) == valueToCheck; } And use it like this: if(item.IsNullOrValue(0)){} // but you don’t get much from it
You can use a regular expression that matches zeroes at the beginning of the string: s = s.replace(/^0+/, ”);
Updated Generalized to maintain precision and handle unseen values: import decimal import random def format_number(num): try: dec = decimal.Decimal(num) except: return ‘bad’ tup = dec.as_tuple() delta = len(tup.digits) + tup.exponent digits=””.join(str(d) for d in tup.digits) if delta <= 0: zeros = abs(tup.exponent) – len(tup.digits) val=”0.” + (‘0’*zeros) + digits else: val = digits[:delta] + (‘0’*tup.exponent) … Read more
You can use sprintf: http://php.net/manual/en/function.sprintf.php <?php $num = 4; $num_padded = sprintf(“%02d”, $num); echo $num_padded; // returns 04 ?> It will only add the zero if it’s less than the required number of characters. Edit: As pointed out by @FelipeAls: When working with numbers, you should use %d (rather than %s), especially when there is … Read more
Check if the denominator is zero before dividing. This avoids the overhead of catching the exception, which may be more efficient if you expect to be dividing by zero a lot. def weird_division(n, d): return n / d if d else 0
This “feature” was result of a bugfix in EL which was introduced as per Tomcat 6.0.16. As per chapter 1.18.3 of the EL specification, a value of number type which is null should be coerced to 0. Before Tomcat 6.0.16 this was “incorrectly” been coerced to an empty string. After all, an empty string was … Read more
You can use javascript’s toFixed method (source), you don’t need jQuery. Example: var number = 258.2; var rounded = number.toFixed(2); // rounded = 258.20 Edit: Electric Toolbox link has succumbed to linkrot and blocks the Wayback Machine so there is no working URL for the source.
Yes, divide by it. 1 / +0.0f is +Infinity, but 1 / -0.0f is -Infinity. It’s easy to find out which one it is with a simple comparison, so you get: if (1 / x > 0) // +0 here else // -0 here (this assumes that x can only be one of the two … Read more