You don’t have a let property. Also, the get property is returning the entire array, rather than just the element in question. Change the return type of Property Get from Double() to just plain Double. Add Property Let. Note that it takes two inputs, but only one is passed to it. The last variable (MyValue, … Read more
See microsoft/TypeScript#30406 for a canonical answer. For the question, “why does the compiler think that pop() might return undefined even when I check the array’s length“, the short answer is “because the TypeScript standard library’s call signature for the pop() method on Array<T> returns T | undefined“: interface Array<T> { // … elided pop(): T … Read more
You can compute the norm of each column or row of a matrix yourself by using element-wise arithmetic operators and functions defined to operate over given matrix dimensions (like SUM and MAX). Here’s how you could compute some column-wise norms for a matrix M: twoNorm = sqrt(sum(abs(M).^2,1)); %# The two-norm of each column pNorm = … Read more
There is a trivial O(n^2) algorithm, but you can do this in O(n). E.g.: A = [a, b, c, d, e] P = [4, 3, 2, 0, 1] We can swap each element in A with the right element required by P, after each swap, there will be one more element in the right position, … Read more
This has nothing to do with tuples. Anyway, it isn’t possible to convert from an array to a tuple in the general case, as the arrays can have any length, and the arity of a tuple must be known at compile time. However, you can solve your problem by providing overloads: // This function does … Read more
You can use the merge sort algorithm. In the merge algorithm’s loop, the left and right halves are both sorted ascendingly, and we want to merge them into a single sorted array. Note that all the elements in the right side have higher indexes than those in the left side. Assume array[leftIndex] > array[rightIndex]. This … Read more
Yes. You can assign arrays to the XValues and Values properties of a Series object on a chart. Example: Dim c As Chart Dim s As Series Dim myData As Variant Set c = ActiveChart ‘ Assumes a chart is currently active in Excel… Set s = c.SeriesCollection(1) myData = Array(9, 6, 7, 1) ‘ … Read more
let array1: [Double] = [1.2, 2.4, 20.0, 10.9, 1.5] let array2: [Int] = [1, 0, 2, 0, 3] // use zip to combine the two arrays and sort that based on the first let combined = zip(array1, array2).sorted {$0.0 < $1.0} print(combined) // “[(1.2, 1), (1.5, 3), (2.4, 0), (10.9, 0), (20.0, 2)]” // use … Read more
Here’s one implementation, but whether it is the one you are after is completely impossible to say, because you have not specified what you think the answer should be: let answer = zip(array1, array2).map {$0.0 == $0.1} That gives you a list of Bool values, true if the answer matches the right answer, false if … Read more