Bash script and /bin/bash^M: bad interpreter: No such file or directory [duplicate]
Run following command in terminal sed -i -e ‘s/\r$//’ scriptname.sh Then try ./scriptname.sh It should work.
bash
How can I exclude all “permission denied” messages from “find”?
Use: find . 2>/dev/null > files_and_folders This hides not just the Permission denied errors, of course, but all error messages. If you really want to keep other possible errors, such as too many hops on a symlink, but not the permission denied ones, then you’d probably have to take a flying guess that you don’t … Read more
In bash, how do I expand a wildcard while it’s inside double quotes?
Move the quotes. Just don’t quote the *. Probably also good not to quote the ~. go() { cd ~/”project/entry ${1}”* } That being said if this matches more than one thing cd will use the first match and ignore all the other matches.
How to use aliases defined in .bashrc in other scripts?
You need to do shopt -s expand_aliases in the script in addition to sourcing ~/.bashrc.
Extract data from log file in specified range of time [duplicate]
You can use sed for this. For example: $ sed -n ‘/Feb 23 13:55/,/Feb 23 14:00/p’ /var/log/mail.log Feb 23 13:55:01 messagerie postfix/smtpd[20964]: connect from localhost[127.0.0.1] Feb 23 13:55:01 messagerie postfix/smtpd[20964]: lost connection after CONNECT from localhost[127.0.0.1] Feb 23 13:55:01 messagerie postfix/smtpd[20964]: disconnect from localhost[127.0.0.1] Feb 23 13:55:01 messagerie pop3d: Connection, ip=[::ffff:127.0.0.1] … How it works … Read more
Bash script – store stderr in a variable [duplicate]
Try redirecting stderr to stdout and using $() to capture that. In other words: VAR=$((your-command-including-redirect) 2>&1) Since your command redirects stdout somewhere, it shouldn’t interfere with stderr. There might be a cleaner way to write it, but that should work. Edit: This really does work. I’ve tested it: #!/bin/bash BLAH=$(( ( echo out >&1 echo … Read more
How to perform a for loop on each character in a string in Bash?
You can use a C-style for loop: foo=string for (( i=0; i<${#foo}; i++ )); do echo “${foo:$i:1}” done ${#foo} expands to the length of foo. ${foo:$i:1} expands to the substring starting at position $i of length 1.
Command substitution: backticks or dollar sign / paren enclosed? [duplicate]
There are several questions/issues here, so I’ll repeat each section of the poster’s text, block-quoted, and followed by my response. What’s the preferred syntax, and why? Or are they pretty much interchangeable? I would say that the $(some_command) form is preferred over the `some_command` form. The second form, using a pair of backquotes (the “`” … Read more
Random number from a range in a Bash Script
shuf -i 2000-65000 -n 1 Enjoy! Edit: The range is inclusive.
How to get Maven project version to the bash command line
The Maven Help Plugin is somehow already proposing something for this: help:evaluate evaluates Maven expressions given by the user in an interactive mode. Here is how you would invoke it on the command line to get the ${project.version}: mvn org.apache.maven.plugins:maven-help-plugin:2.1.1:evaluate \ -Dexpression=project.version As noted in the comments by Seb T, to only print the version … Read more