There is no difference, under the hood it’s all varlena (variable length array). Check this article from Depesz: http://www.depesz.com/index.php/2010/03/02/charx-vs-varcharx-vs-varchar-vs-text/ A couple of highlights: To sum it all up: char(n) – takes too much space when dealing with values shorter than n (pads them to n), and can lead to subtle errors because of adding trailing … Read more
Single quotes are a standard java String Double quotes are a templatable String, which will either return a GString if it is templated, or else a standard Java String. For example: println ‘hi’.class.name // prints java.lang.String println “hi”.class.name // prints java.lang.String def a=”Freewind” println “hi $a” // prints “hi Freewind” println “hi $a”.class.name // prints … Read more
You can do it with eval but you really should not eval([‘x’, num2str(i), ‘ = ‘, num2str(i)]); %//Not recommended Rather use a cell array: x{i} = i
Variables are expanded in double quoted strings, but not in single quoted strings: $ name=World $ echo “Hello $name” Hello World $ echo ‘Hello $name’ Hello $name If you can simply switch quotes, do so. If you prefer sticking with single quotes to avoid the additional escaping, you can instead mix and match quotes in … Read more
assign is what you are looking for. assign(“x”, 5) x [1] 5 but buyer beware. See R FAQ 7.21 http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f
There are several ways to do this. Common methods use recursion, memoization, or dynamic programming. The basic idea is that you produce a list of all strings of length 1, then in each iteration, for all strings produced in the last iteration, add that string concatenated with each character in the string individually. (the variable … Read more
I’ve done a lot of work on this kind of parsing. Because there are errors you won’t get 100% accuracy, but there are a few things you can do to get most of the way there, and then do a visual BS test. Here’s the general way to go about it. It’s not code, because … Read more
This is problem: if [[$variable == $blanko]]; Spaces are required inside square brackets, use it like this: [[ “$variable” == “$blanko” ]] && echo “Nichts da!” || echo “$variable”
A simple answer is: echo ” lol ” | xargs Xargs will do the trimming for you. It’s one command/program, no parameters, returns the trimmed string, easy as that! Note: this doesn’t remove all internal spaces so “foo bar” stays the same; it does NOT become “foobar”. However, multiple spaces will be condensed to single … Read more
The following is an attempt to describe the Ukkonen algorithm by first showing what it does when the string is simple (i.e. does not contain any repeated characters), and then extending it to the full algorithm. First, a few preliminary statements. What we are building, is basically like a search trie. So there is a … Read more