View permissions in Django [duplicate]

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Adding ‘view’ permission to default permissions list

Your solution works, but you should really avoid editing source code if possible. There’s a few ways to accomplish this within the framework:

1. Add the permission during post_syncdb():

In a file under your_app/management/

from django.db.models.signals import post_syncdb
from django.contrib.contenttypes.models import ContentType
from django.contrib.auth.models import Permission

def add_view_permissions(sender, **kwargs):
    """
    This syncdb hooks takes care of adding a view permission too all our 
    content types.
    """
    # for each of our content types
    for content_type in ContentType.objects.all():
        # build our permission slug
        codename = "view_%s" % content_type.model

        # if it doesn't exist..
        if not Permission.objects.filter(content_type=content_type, codename=codename):
            # add it
            Permission.objects.create(content_type=content_type,
                                      codename=codename,
                                      name="Can view %s" % content_type.name)
            print "Added view permission for %s" % content_type.name

# check for all our view permissions after a syncdb
post_syncdb.connect(add_view_permissions)

Whenever you issue a ‘syncdb’ command, all content types can be
checked to see if they have a ‘view’ permission, and if not, create
one.

2. Add the permission to the Meta permissions option:

Under every model you would add something like this to its Meta options:

class Pizza(models.Model):
    cheesiness = models.IntegerField()

    class Meta:
        permissions = (
            ('view_pizza', 'Can view pizza'),
        )

This will accomplish the same as 1 except you have to manually add it to each class.

3. NEW in Django 1.7, Add the permission to the Meta default_permissions option:

In Django 1.7 they added the default_permissions Meta option. Under every model you would add ‘view’ to the default_permissions option:

class Pizza(models.Model):
    cheesiness = models.IntegerField()

    class Meta:
        default_permissions = ('add', 'change', 'delete', 'view')

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