No, Function.call.apply
and Function.apply
are not the same in this case.
Let’s say the original caller invokes
Foo.method(t, x, y, z)
With call and apply together, as in the JavaScript Garden code. This executes
Function.call.apply(Foo.prototype.method, arguments);
which is (loosely, writing arguments
in array-notation):
Function.call.apply(Foo.prototype.method, [t, x, y, z]);
which invokes Function.call
with this==Foo.prototype.method
:
Foo.prototype.method.call(t, x, y, z)
which calls Foo.prototype.method
with this
set to t
and arguments x
, y
, and z
. Sweet. Just like in the comments. We have successfully made a wrapper.
Now suppose you left said just Function.apply
instead of Function.call.apply
, which you claim is semantically equivalent. You would have
Function.apply(Foo.prototype.method, arguments);
which is (loosely)
Function.apply(Foo.prototype.method, [t, x, y, z]);
which calls the function Function
(ugh!) with this
set to Foo.prototype.method
and arguments t
, x
, y
, and z
.
Not the same at all.