Why does a=(b++) have the same behavior as a=b++?

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However, I expected the parentheses to have b1 incremented before its value is assigned to a1

You should not have expected that: placing parentheses around an increment expression does not alter the application of its side effects.

Side effects (in this case, it means writing 11 into b1) get applied some time after retrieving the current value of b1. This could happen before or after the full assignment expression is evaluated completely. That is why a post-increment will remain a post-increment, with or without parentheses around it. If you wanted a pre-increment, place ++ before the variable:

a1 = ++b1;

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