Why does using multiplication operator on list create list of pointers? [duplicate]

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The behaviour is not specific to the repetition operator (*). For example, if you concatenate two lists using +, the behaviour is the same:

In [1]: a = [[1]]

In [2]: b = a + a

In [3]: b
Out[3]: [[1], [1]]

In [4]: b[0][0] = 10

In [5]: b
Out[5]: [[10], [10]]

This has to do with the fact that lists are objects, and objects are stored by reference. When you use * et al, it is the reference that gets repeated, hence the behaviour that you’re seeing.

The following demonstrates that all elements of rows have the same identity (i.e. memory address in CPython):

In [6]: rows = [['']*5]*5

In [7]: for row in rows:
   ...:     print id(row)
   ...:     
   ...:     
15975992
15975992
15975992
15975992
15975992

The following is equivalent to your example except it creates five distinct lists for the rows:

rows = [['']*5 for i in range(5)]

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