How does the “scala.sys.process” from Scala 2.9 work?

by

First import:

import scala.sys.process.Process

then create a ProcessBuilder

val pb = Process("""ipconfig.exe""")

Then you have two options:

  1. run and block until the process exits

    val exitCode = pb.!

  2. run the process in background (detached) and get a Process instance

    val p = pb.run

    Then you can get the exitcode from the process with (If the process is still running it blocks until it exits)

    val exitCode = p.exitValue

If you want to handle the input and output of the process you can use ProcessIO:

import scala.sys.process.ProcessIO
val pio = new ProcessIO(_ => (),
                        stdout => scala.io.Source.fromInputStream(stdout)
                          .getLines.foreach(println),
                        _ => ())
pb.run(pio)

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