Here is one way to do it.
Since you want the distinct counts as well, it can be done simply by grouping the rows twice. The first GROUP BY
will remove duplicates, the second GROUP BY
will produce the final result.
WITH
Sitings
AS
(
SELECT * FROM (VALUES
(1, 'Florida', 'Orlando', 'bird'),
(2, 'Florida', 'Orlando', 'dog'),
(3, 'Arizona', 'Phoenix', 'bird'),
(4, 'Arizona', 'Phoenix', 'dog'),
(5, 'Arizona', 'Phoenix', 'bird'),
(6, 'Arizona', 'Phoenix', 'bird'),
(7, 'Arizona', 'Phoenix', 'bird'),
(8, 'Arizona', 'Flagstaff', 'dog')
) F (ID, State, City, Siting)
)
,CTE_Animals
AS
(
SELECT
State, City, Siting
FROM Sitings
GROUP BY State, City, Siting
)
SELECT
State, City, COUNT(1) AS [# Of Sitings], STRING_AGG(Siting,',') AS Animals
FROM CTE_Animals
GROUP BY State, City
ORDER BY
State
,City
;
Result
+---------+-----------+--------------+----------+
| State | City | # Of Sitings | Animals |
+---------+-----------+--------------+----------+
| Arizona | Flagstaff | 1 | dog |
| Arizona | Phoenix | 2 | bird,dog |
| Florida | Orlando | 2 | bird,dog |
+---------+-----------+--------------+----------+
If you are still getting an error message about exceeding 8000 characters, then cast the values to varchar(max)
before STRING_AGG
.
Something like
STRING_AGG(CAST(Siting AS varchar(max)),',') AS Animals