There are some facts about c you’re missing: There’s no string datatype. A string is just a sequence of char ending with a 0 byte. What you use here is a string literal — the compiler translates it to an array of char and automatically adds the 0 at the end. An array when passed … Read more
To know how all these three code blocks works, you got to start reading good C book specially array and pointers concept. Case 1 :- In the below code block int main(void) { char x[] = “gate2011”; char *ptr = x; printf (“%s”, ptr+ptr[3]-ptr[1]); return 0; } It looks like x[0] x[1] x[2] x[3] x[4] … Read more
Error was in v_push_back implementation : v->e_array = check_a(memcpy((void*)((char*)v->e_array + (v->no_e * v->e_sz)) ,new_val, v->e_sz)); //pointer has not to be saved check_a(memcpy((void*)((char*)v->e_array + (v->no_e * v->e_sz)) ,new_val, v->e_sz)); Because memcpy returns a pointer , in this case, to the last element of the array so we would have lost access to all previous memory
You need A separate index for writing to szBuffer Code that adds a zero termination to szBuffer Like: int j = 0; // Index for storing in szBuffer for (int i = 0; i < StrLenght – 1; i++) { if (szPattern[i] == ‘%’) { // DO stuff…. } else { szBuffer[j] = szPattern[i]; // … Read more
You need to parse it to int Integer.parseInt(String.valueOf(s.charAt(0))) + Integer.parseInt(String.valueOf(s.charAt(1)))
The below code works in getting the last index of a certain character: public int lastIndex(char a, char[] data) { int max=-1; for(int i=0; i<data.length; i++) { if(data[i]==a) { max=i; } } return max; } It works by going through the array and finding the latest occurrence of a certain character. The variable ‘max’ is … Read more
You are confusing strings and characters. A character literal is enclosed in ‘. A string literal is enclosed in ” and is an array of characters. e.g.: “This is a string literal” ‘c’ // this is character To test if a char is not z for instance, you write: char c = …; if (c … Read more
C# doesn’t have a built-in way of handling symbols at run-time. Not every language out there is LISP 🙂 In the general case, you’re talking about a compiler – something that takes code as input, and produces executable. There’s many ways to invoke the C# compiler in C#, and they’re very easy to find, so … Read more
Here char *firstName[50]; firstName is array of 50 character pointer, and if you want to store anything into each of these char pointer, you need to allocate memory for them. For e.g for (int counter = 0; counter < 10; counter ++) { firstName[counter] = malloc(SIZE_FIRST); /* memory allocated for firstName[counter], now you can store … Read more
You’re initializing the variable myChar as type char, but trying to fit a String inside. Java uses double quotes (“”) for Strings and single quotes (”) for chars. To fix this is simple: char myChar=”\u00A9″; The single quotes make ALL the difference!