I do not know whether this solution is more efficient, but maybe it is more readable and easier to code: #include <iostream> #include <cstdlib> int main() { const int magicNumber = 32640; const int maxOffset = 1920; int n; std::cin >> n; int y = 20; const std::div_t divresult = std::div(n, magicNumber); if (divresult.rem > … Read more
Remember, C and C++ are somewhat expressive languages. That means most expressions return a value. If you don’t do anything with that value, it’s lost to the sands of time. The expression (a++) will return a‘s former value. As mentioned before, if its return value is not used right then and there, then it’s the … Read more
Try something like this: System.out.println( “Farenheit | Celsius | Kelvin” ); // For loop for ( double f = startfarh ; f <= endfarh ; f += 1d ) { double c = ( f – 32 ) / 1.8d; double k = c + 273.15; System.out.printf( “%7.2f°F = %6.2f°C = %6.2fK%n”, f, c, k … Read more
You can use another counter to check when you’ve done 50 iterations <?php $counter = 1; $MiniCounter = 0; foreach ($numbers as $num) { // Pre-increment since $MiniCounter starts by 0 if (++$MiniCounter >= 50) // using >= 50 because, who knows, $MiniCounter may jump magically from 49 to 51 { $MiniCounter = 0; //reset … Read more
Why does this code print 10 times “Hello world.”? No, this will be an infinite loop because the following statement resets the value of k to 1: k=+1; Also, k=k++ will not change the value of k because it is processed something like int temp = k; k++; k = temp; You can try the … Read more