long-integer - w3toppers.com

Convert Double to Binary representation?

Long.toBinaryString(Double.doubleToRawLongBits(d)) appears to work just fine. System.out.println(“0: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(0D))); System.out.println(“1: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(1D))); System.out.println(“2: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(2D))); System.out.println(“2^900: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(Math.pow(2, 900)))); System.out.println(“Double.MAX_VALUE: 0b” + Long.toBinaryString(Double.doubleToRawLongBits(Double.MAX_VALUE))); /* prints: 0: 0b0 1: 0b11111111110000000000000000000000000000000000000000000000000000 2: 0b100000000000000000000000000000000000000000000000000000000000000 2^900: 0b111100000110000000000000000000000000000000000000000000000000000 Double.MAX_VALUE: 0b111111111101111111111111111111111111111111111111111111111111111 */

“OverflowError: Python int too large to convert to C long” on windows but not mac

You’ll get that error once your numbers are greater than sys.maxsize: >>> p = [sys.maxsize] >>> preds[0] = p >>> p = [sys.maxsize+1] >>> preds[0] = p Traceback (most recent call last): File “<stdin>”, line 1, in <module> OverflowError: Python int too large to convert to C long You can confirm this by checking: >>> … Read more

What is the conversion specifier for printf that formats a long?

Put an l (lowercased letter L) directly before the specifier. unsigned long n; long m; printf(“%lu %ld”, n, m);

How to printf long long

%lld is the standard C99 way, but that doesn’t work on the compiler that I’m using (mingw32-gcc v4.6.0). The way to do it on this compiler is: %I64d So try this: if(e%n==0)printf(“%15I64d -> %1.16I64d\n”,e, 4*pi); and scanf(“%I64d”, &n); The only way I know of for doing this in a completely portable way is to use … Read more

warning: left shift count >= width of type

long may be a 64-bit type, but 1 is still an int. You need to make 1 a long int using the L suffix: unsigned long x = 1UL << 32; (You should also make it unsigned using the U suffix as I’ve shown, to avoid the issues of left shifting a signed integer. There’s … Read more

How to convert a String to long in javascript?

JavaScript has a Number type which is a 64 bit floating point number*. If you’re looking to convert a string to a number, use either parseInt or parseFloat. If using parseInt, I’d recommend always passing the radix too. use the Unary + operator e.g. +”123456″ use the Number constructor e.g. var n = Number(“12343”) *there … Read more

Multiplication of two integers in C++

The ints are not promoted to long long before multiplication, they remain ints and the product as well. Then the product is cast to long long, but too late, overflow has struck. Having one of a or b long long should work as well, as the other would be promoted.

Java creating byte array whose size is represented by a long

(It is probably a bit late for the OP, but it might still be useful for others) Unfortunately Java does not support arrays with more than 231−1 elements. The maximum consumption is 2 GiB of space for a byte[] array, or 16 GiB of space for a long[] array. While it is probably not applicable … Read more

Java: Checking if a bit is 0 or 1 in a long

I’d use: if ((value & (1L << x)) != 0) { // The bit was set } (You may be able to get away with fewer brackets, but I never remember the precedence of bitwise operations.)

C: Casting minimum 32-bit integer (-2147483648) to float gives positive number (2147483648.0)

Replace #define INT32_MIN (-2147483648L) with #define INT32_MIN (-2147483647 – 1) -2147483648 is interpreted by the compiler to be the negation of 2147483648, which causes overflow on an int. So you should write (-2147483647 – 1) instead. This is all C89 standard though. See Steve Jessop’s answer for C99. Also long is typically 32 bits on … Read more