long-integer - w3toppers.com

How do I convert Long to byte[] and back in java

public byte[] longToBytes(long x) { ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES); buffer.putLong(x); return buffer.array(); } public long bytesToLong(byte[] bytes) { ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES); buffer.put(bytes); buffer.flip();//need flip return buffer.getLong(); } Or wrapped in a class to avoid repeatedly creating ByteBuffers: public class ByteUtils { private static ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES); public static byte[] longToBytes(long x) { buffer.putLong(0, … Read more

Why do these two multiplication operations give different results?

long oneYearWithL = 1000*60*60*24*365L; long oneYearWithoutL = 1000*60*60*24*365; Your first value is actually a long (Since 365L is a long, and 1000*60*60*24 is an integer, so the result of multiplying a long value with an integer value is a long value. But 2nd value is an integer (Since you are mulitplying an integer value with … Read more

Break long word with CSS

What you need is word-wrap: break-word;, this property will force the non spaced string to break inside the div Demo div { width: 20px; word-wrap: break-word; }

Division of integers in Java [duplicate]

Converting the output is too late; the calculation has already taken place in integer arithmetic. You need to convert the inputs to double: System.out.println((double)completed/(double)total); Note that you don’t actually need to convert both of the inputs. So long as one of them is double, the other will be implicitly converted. But I prefer to do … Read more

Why Use Integer Instead of Long?

Integer variables are stored as 16-bit (2-byte) numbers Office VBA Reference Long (long integer) variables are stored as signed 32-bit (4-byte) numbers Office VBA Reference So, the benefit is in reduced memory space. An Integer takes up half the memory that a Long does. Now, we are talking about 2 bytes, so it’s not going … Read more

How do I add an "L" to the end of an integer?

It seems the API you’re using scheduler.scheduleSyncRepeatingTask() expects the last two parameters to be of type long. Since, an int can implicitly fit into a long, passing timeBetween as it is will work just fine. Same goes for the second parameter too. You can pass 0 instead of 0L there as well. It works out … Read more