How to handle arbitrarily large integers
If you need larger than 32-bits you could consider using 64-bit integers (long long), or use or write an arbitrary precision math library, e.g. GNU MP.
If you need larger than 32-bits you could consider using 64-bit integers (long long), or use or write an arbitrary precision math library, e.g. GNU MP.
Going by the standard, all that’s guaranteed is: int must be at least 16 bits long must be at least 32 bits long long must be at least 64 bits On major 32-bit platforms: int is 32 bits long is 32 bits as well long long is 64 bits On major 64-bit platforms: int is … Read more
a) Can you explain to me the difference between int64_t and long (long int)? In my understanding, both are 64 bit integers. Is there any reason to choose one over the other? The former is a signed integer type with exactly 64 bits. The latter is a signed integer type with at least 32 bits. … Read more
The bindingConfiguration needs to have the name you assign to the netTcpinding element – “LargeBuffer” or “LongFields” won’t mean anything unless there is a binding element in the config file with that name. That is why your service won’t start when you put that in – you most likely got a configuration error message of … Read more
Long.decode(str) accepts a variety of formats: Accepts decimal, hexadecimal, and octal numbers given by the following grammar: DecodableString: Signopt DecimalNumeral Signopt 0x HexDigits Signopt 0X HexDigits Signopt # HexDigits Signopt 0 OctalDigits Sign: – But in your case that won’t help, your String is beyond the scope of what long can hold. You need a … Read more
double supports Infinity double inf = Double.POSITIVE_INFINITY; System.out.println(inf + 5); System.out.println(inf – inf); // same as Double.NaN System.out.println(inf * -1); // same as Double.NEGATIVE_INFINITY prints Infinity NaN -Infinity note: Infinity – Infinity is Not A Number.
%lu is the correct format for unsigned long. Sounds like there are other issues at play here, such as memory corruption or an uninitialized variable. Perhaps show us a larger picture?
Not with built-in JSON.parse. You’ll need to parse it manually and treat values as string (if you want to do arithmetics with them there is bignumber.js) You can use Douglas Crockford JSON.js library as a base for your parser. EDIT2 ( 7 years after original answer ) – it might soon be possible to solve … Read more
Put an l (lowercased letter L) directly before the specifier. unsigned long n; long m; printf(“%lu %ld”, n, m);
Starting from Java 7 (or Android API Level 21 = 5.0+) you could directly use ThreadLocalRandom.current().nextLong(n) (for 0 ≤ x < n) and ThreadLocalRandom.current().nextLong(m, n) (for m ≤ x < n). See @Alex‘s answer for detail. If you are stuck with Java 6 (or Android 4.x) you need to use an external library (e.g. org.apache.commons.math3.random.RandomDataGenerator.getRandomGenerator().nextLong(0, … Read more