Why subclass in another package cannot access a protected method?
Protected methods can only be accessible through inheritance in subclasses outside the package. And hence the second approach tryMeProtected(); works. The code below wont compile because we are not calling the inherited version of protected method. Class1 c = new Class1(); c.tryMeProtected(); // ERROR: tryMeProtected() has protected access in Class1 Follow this stackoverflow link for … Read more