The Python 3 range() object doesn’t produce numbers immediately; it is a smart sequence object that produces numbers on demand. All it contains is your start, stop and step values, then as you iterate over the object the next integer is calculated each iteration. The object also implements the object.__contains__ hook, and calculates if your … Read more
You chould exchange conditions in the while statement while ( i < arr.size() && a != arr[i] ) i++; Also this condition is wrong while(!text.eof()) { text>>a; The eof state can occur after statement text>>a; in the block of the while. Change it to while ( text >> a )
You need to implement if-else if- else statements: if (hun > 100) { std::cout << “Pick a number LESS than 100. “; } else if (hun > 50) { std::cout << “Your number is greater than 50. “; } else if (hun < 50) { std::cout << “Your number is less than 50. “; } … Read more
The range command returns a list of values. If your ‘start’ is greater than your ‘end’ value, an empty list is returned. The default increment value is positive 1. You can, however, use a third argument as the increment value. You can pass it as -1, and then the range() will return a decreasing value, … Read more
items = [1, 2, 3, 4, 5, 6, 7, 8, 9] for item in items: if 5 <= item <= 10: print(item) You might find Python for Beginners useful.
a = range(10) a = filter(lambda n: n%2 != 0, a) it will give you [1, 3, 5, 7, 9] As you can see, no more six (and the same will happen with any multiple of six) then, if you delete multiples of three a = filter(lambda n: n%3 != 0, a) a will be … Read more