XML syntax validation in Java [closed]

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You can check if an XML document is well-formed using the following code:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setValidating(false);
factory.setNamespaceAware(true);

DocumentBuilder builder = factory.newDocumentBuilder();

builder.setErrorHandler(new SimpleErrorHandler());    
// the "parse" method also validates XML, will throw an exception if misformatted
Document document = builder.parse(new InputSource("document.xml"));

The SimpleErrorHandler class referred to in the above code is as follows:

public class SimpleErrorHandler implements ErrorHandler {
    public void warning(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }

    public void error(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }

    public void fatalError(SAXParseException e) throws SAXException {
        System.out.println(e.getMessage());
    }
}

This came from this website, which provides various methods for validating XML with Java. Note also that this method loads an entire DOM tree into memory, see comments for alternatives if you want to save on RAM.

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