C++ uses the limits defined in the C standard (C++: 18.3.2 (c.limits), C: 5.2.4.2.1): LONG_MIN -2147483647 // -(2^31 – 1) LONG_MAX +2147483647 // 2^31 – 1 So you are guaranteed that a long is at least 32 bits. And if you want to follow the long circuitous route to whether LONG_MIN/LONG_MAX are representable by a … Read more
long and long int are identical. So are long long and long long int. In both cases, the int is optional. As to the difference between the two sets, the C++ standard mandates minimum ranges for each, and that long long is at least as wide as long. The controlling parts of the standard (C++11, … Read more
Java 8 has Math.multiplyExact, Math.addExact etc. for ints and long. These throw an unchecked ArithmeticException on overflow.
This question has been asked here before: Who has solved the long-word-breaks-my-div problem? (hint: not stackoverflow) word wrap in css / js CSS: how can I force a long string (without any blank) to be wrapped in XUL and/or HTML CSS overflow with long URL Long story short: As far as CSS solutions go you … Read more
The letters 100000000000 make up a literal integer constant, but the value is too large for the type int. You need to use a suffix to change the type of the literal, i.e. long long num3 = 100000000000LL; The suffix LL makes the literal into type long long. C is not “smart” enough to conclude … Read more
For float have a look at sys.float_info: >>> import sys >>> sys.float_info sys.floatinfo(max=1.7976931348623157e+308, max_exp=1024, max_10_exp=308, min=2.2 250738585072014e-308, min_exp=-1021, min_10_exp=-307, dig=15, mant_dig=53, epsil on=2.2204460492503131e-16, radix=2, rounds=1) Specifically, sys.float_info.max: >>> sys.float_info.max 1.7976931348623157e+308 If that’s not big enough, there’s always positive infinity: >>> infinity = float(“inf”) >>> infinity inf >>> infinity / 10000 inf The long type has … Read more
There are specific suffixes for long (e.g. 39832L), float (e.g. 2.4f) and double (e.g. -7.832d). If there is no suffix, and it is an integral type (e.g. 5623), it is assumed to be an int. If it is not an integral type (e.g. 3.14159), it is assumed to be a double. In all other cases … Read more
The Date constructor (click the link!) accepts the time as long in milliseconds, not seconds. You need to multiply it by 1000 and make sure that you supply it as long. Date d = new Date(1220227200L * 1000); This shows here Sun Aug 31 20:00:00 GMT-04:00 2008
You should add L: long i = 12345678910L;. Yes. BTW: it doesn’t have to be an upper case L, but lower case is confused with 1 many times :).
Add a capital L to the end: long value = 9223372036854775807L; Otherwise, the compiler will try to parse the literal as an int, hence the error message