You can use any of these: # Create a range that does not contain 50 for i in [x for x in xrange(100) if x != 50]: print i # Create 2 ranges [0,49] and [51, 100] (Python 2) for i in range(50) + range(51, 100): print i # Create a iterator and skip 50 … Read more
Yes, it is possible. For example, for gcc you can use __builtin_unreachable to tell the compiler about impossible conditions, like so: if (value < 0 || value > 36) __builtin_unreachable(); We can wrap the condition above in a macro: #define assume(cond) do { if (!(cond)) __builtin_unreachable(); } while (0) And use it like so: assume(x … Read more
Since I was free, I created an example for you Create a Userform and place a ComboBox, A RefEdit Control and a Label Next paste this code in the Userform Private Sub UserForm_Initialize() Dim wb As Workbook ‘~~> Get the name of all the workbooks in the combobox For Each wb In Application.Workbooks ComboBox1.AddItem wb.Name … Read more
IMHO, the easiest way to generate a random number in a [min..max] range with window.crypto.getRandomValues() is described here. An ECMAScript 2015-syntax code, in case the link is TL;TR: function getRandomIntInclusive(min, max) { const randomBuffer = new Uint32Array(1); window.crypto.getRandomValues(randomBuffer); let randomNumber = randomBuffer[0] / (0xffffffff + 1); min = Math.ceil(min); max = Math.floor(max); return Math.floor(randomNumber * … Read more
You’re getting the muddled green because of the way you’re creating your gradient in RBG space. To get a “cleaner” gradient, you can use the HSV model as mentioned in the answer of the question you linked to. RGB gradient (top) vs HSV (bottom) By scaling the H (hue) value between 0 (red) and 120 … Read more
I think the 2009 paper “Pairs do not make good ranges” by Alisdair Meredith is at least part of the answer. Basically, many algorithms return pairs of iterators that are actually not guaranteed to be valid ranges. It seems they removed the support for pair<iterator,iterator> from the for-range loop for this reason. However, the proposed … Read more
import bisect bisect.bisect_left([100,300,500,800,1000], p) here the docs: bisect
Take advantage of PHP’s ability to increment characters “perl-style” $letters = array(); $letter=”A”; while ($letter !== ‘AAA’) { $letters[] = $letter++; } But you could also use simple integer values, and take advantage of PHPExcel’s built-in PHPExcel_Cell::stringFromColumnIndex() method EDIT From PHP 5.5, you can also use Generators to avoid actually building the array in memory … Read more
Off the top of my head, no. I think the best you could do is something like this: def loop(f,n): for i in xrange(n): f() loop(lambda: <insert expression here>, 5) But I think you can just live with the extra i variable. Here is the option to use the _ variable, which in reality, is … Read more