Uncaught TypeError: Cannot use ‘in’ operator to search for ‘length’ in

by

The in operator only works on objects. You are using it on a string. Make sure your value is an object before you using $.each. In this specific case, you have to parse the JSON:

$.each(JSON.parse(myData), ...);

More Related Contents:

  1. Jquery getJSON populate select menu question
  2. how to read json result in jquery?
  3. JSON string to JS object
  4. Add new row in html dynamically using jQuery
  5. Random JSON where x is true
  6. Serializing to JSON in jQuery [duplicate]
  7. Convert JSON array to an HTML table in jQuery
  8. Merge two json/javascript arrays in to one array
  9. What is the $$hashKey added to my JSON.stringify result
  10. How to search JSON tree with jQuery
  11. Get unique results from JSON array using jQuery
  12. Load local JSON file into variable
  13. how to use json file in html code
  14. jQuery JSON to string?
  15. How to escape a JSON string to have it in a URL?
  16. jQuery AJAX polling for JSON response, handling based on AJAX result or JSON content
  17. AJAX call and clean JSON but Syntax Error: missing ; before statement
  18. sort JSON by date
  19. Loop and get key/value pair for JSON array using jQuery
  20. jQuery getJSON save result into variable [duplicate]
  21. Jquery getJSON cross domain problems
  22. How to send data from HTML form to Google Spreadsheet using JavaScript?
  23. Creating a JSON dynamically with each input value using jquery
  24. How can I get javascript to read from a .json file?
  25. Nested JSON: How to add (push) new items to an object?
  26. Why does the jQuery JSON parser need double escaping for backslashes?
  27. jQuery uses (new Function(“return ” + data))(); instead of eval(data); to parse JSON, why?
  28. creating highchart with ajax json data
  29. Ordered JSONObject
  30. Grouping JSON by values

Leave a Comment