Weird closure behavior in python

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As @thg435 points out, a lambda will not encapsulate the values at that moment, but rather the scope. There are too small ways you can address this:

lambda default argument “hack”

[ lambda v=i: v for i in [ 1, 2, 3 ] ]

Or use functools.partial

from functools import partial
[ partial(lambda v: v, i) for i in [ 1, 2, 3 ] ]

Essentially you have to move the scope to be local to the function you are creating. Generally I like using partial more often since you can pass it a callable, and any args and kargs to create a callable with a proper closure. Internally, it is wrapping your original callable so the scope is shifted for you.

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