MrAzzman already pointed out how to linearise nested loops. Here is a general solution to linearise n nested loops. 1) Assuming you have a simple nested loop structure like this: %dummy function for demonstration purposes f=@(a,b,c)([a,b,c]); %three loops X=cell(4,5,6); for a=1:size(X,1); for b=1:size(X,2); for c=1:size(X,3); X{a,b,c}=f(a,b,c); end end end 2) Basic linearisation using a for … Read more
Recursion can solve this problem neatly: function callManyTimes(maxIndices, func) { doCallManyTimes(maxIndices, func, [], 0); } function doCallManyTimes(maxIndices, func, args, index) { if (maxIndices.length == 0) { func(args); } else { var rest = maxIndices.slice(1); for (args[index] = 0; args[index] < maxIndices[0]; ++args[index]) { doCallManyTimes(rest, func, args, index + 1); } } } Call it like … Read more
The labels in JavaScript are used mainly with break, or continue in nested loops to be able to break the outer, or continue the outer loop from the code inside inner loop: outer: for (let i = 0; i < 10; i++) { let k = 5; for (let j = 0; j < 10; … Read more
You’re incrementing count in the inner loop which is why you keep getting larger numbers before you want to You could just do this. >>> for i in range(1, 10): print str(i) * i 1 22 333 4444 55555 666666 7777777 88888888 999999999 or if you want the nested loop for some reason from __future__ … Read more
You may use recursion instead with a base condition – void doRecursion(int baseCondition){ if(baseCondition==0) return; //place your code here doRecursion(baseCondition-1); } Now you don’t need to provide the baseCondition value at compile time. You can provide it while calling the doRecursion() method.
This special case of the Knapsack problem is called Subset Sum.
You can use two flatMap then a filter then you can pick the first one or if no result return null : C c1 = listOfAObjects.stream() .flatMap(a -> a.getList().stream()) .flatMap(b -> b.getPr().stream()) .filter(c -> c.getName().equalsIgnoreCase(name)) .findFirst() .orElse(null);
which one is better for performance? It doesn’t matter. what’s the criteria to select a loop? If you just need to walk through all the elements of an object or array, use foreach. Cases where you need for include When you explicitly need to do things with the numeric index, for example: when you need … Read more
Unfortunately, there’s no exit two levels of for statement, but there are a few workarounds to do what you want: Goto. In general, using goto is considered to be bad practice (and rightfully so), but using goto solely for a forward jump out of structured control statements is usually considered to be OK, especially if … Read more
Yes, you can use recursion. Here’s an example where you output all the elements in an array: function printAll($a) { if (!is_array($a)) { echo $a, ‘ ‘; return; } foreach($a as $v) { printAll($v); } } $array = array(‘hello’, array(‘world’, ‘!’, array(‘whats’), ‘up’), array(‘?’)); printAll($array); What you should always remember when doing recursion is that … Read more